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Home » x = \frac-1 \pm \sqrt1^2 - 4(2)(-1)2(2) = \frac-1 \pm \sqrt1 + 84 = \frac-1 \pm 34 - go-checkin.com

x = \frac-1 \pm \sqrt1^2 - 4(2)(-1)2(2) = \frac-1 \pm \sqrt1 + 84 = \frac-1 \pm 34 - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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The radius \(r\) of the inscribed circle is given by:
r = \frac{A}{s} = \frac{54}{18} = 3 \text{ cm}
Thus, the radius of the inscribed circle is \(\boxed{3}\).
A circle is inscribed in a triangle with sides measuring 7 cm, 24 cm,...
First, verify that the triangle is a right triangle using the Pythagor...
25^2 = 7^2 + 24^2 \quad \Rightarrow \quad 625 = 49 + 576 \quad \Righta...
The triangle is confirmed as a right triangle. The area \(A\) of the t...
A = \frac{1}{2} \times 7 \times 24 = 84 \text{ cm}^2
The semi-perimeter \(s\) is:
s = \frac{7 + 24 + 25}{2} = 28 \text{ cm}

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