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Home » Total distance \( = 300 + 1200 + 150 = 1650 \, \textm \). - go-checkin.com

Total distance \( = 300 + 1200 + 150 = 1650 \, \textm \). - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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30^\circ + 60^\circ + 210^\circ + 240^\circ = 540^\circ
إذن، مجموع جميع الزوايا $z$ التي تحقق $\sin(2z) = \frac{\sqrt{3}}{2}$...
السؤال: أوجد إحداثيات الرأس الرابع لهرم رباعي منتظم إذا كانت ثلاثة من...
الحل: لنجعل رؤوس الهرم الرباعي المنتظم هي $A = (0,0,0)$ و $B = (a,a,0)...
s = \sqrt{(a-0)^2 + (a-0)^2 + (0-0)^2} = \sqrt{2a^2} = a\sqrt{2}
نحن بحاجة إلى أن تكون المسافات من $D$ إلى $A$ و $B$ و $C$ جميعها تساوي...
\sqrt{x^2 + y^2 + z^2} = a\sqrt{2} \quad \Rightarrow \quad x^2 + y^2 +...
بعد ذلك، المسافة من $D$ إلى $B$:
\sqrt{(x-a)^2 + (y-a)^2 + z^2} = a\sqrt{2} \quad \Rightarrow \quad (x-...
بتوسيع وتعويض $x^2 + y^2 + z^2 = 2a^2$:

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