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Home » Thus, the circumradius of the triangle is \(\boxed8.5\). - go-checkin.com

Thus, the circumradius of the triangle is \(\boxed8.5\). - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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2r + 2 = (3 - \sqrt{5})r - 3 + \sqrt{5}
2r - (3 - \sqrt{5})r + 5 - \sqrt{5} = 0
r = rac{\sqrt{5} - 5}{-1 + \sqrt{5}} = rac{-(5 - \sqrt{5})}{\sqrt{5}...
Multiply numerator and denominator by \(\sqrt{5} + 1\):
r = -rac{(5 - \sqrt{5})(\sqrt{5} + 1)}{(\sqrt{5} - 1)(\sqrt{5} + 1)}...
Thus, \( r = \sqrt{5} \) or \( r = -\sqrt{5} \). These correspond to p...
e 0\), and \(x
e y\) (to avoid division by zero in the original expression).
Check that \(x = \sqrt{5} y\):
Then \( rac{x+y}{x-y} = rac{\sqrt{5}+1}{\sqrt{5}-1} = rac{3+\sqrt{5...

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