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Home » Solve \( \frac10001 + 9e^-0.2t > 900 \) - go-checkin.com

Solve \( \frac10001 + 9e^-0.2t > 900 \) - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Después de 3 horas: \(66.125 \times 1.15 = 76.04375\) gramos por litro...
#### 76.04375
Un coche se deprecia en valor un 12% cada año. Si el coche inicialment...
El coche se deprecia un 12% cada año, por lo que el factor de deprecia...
Después de 1 año: \(25000 \times 0.88 = 22000\).
Después de 2 años: \(22000 \times 0.88 = 19360\).
Después de 3 años: \(19360 \times 0.88 = 17036.8\).
Después de 4 años: \(17036.8 \times 0.88 = 14991.744\).
#### 14991.744
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