Solution: The ratio of inscribed to plain tablets is $5:3$, so the total number of parts is $5 + 3 = 8$. Since there are 48 tablets, each part represents $ \frac488 = 6 $ tablets. Thus, the number of inscribed tablets is $5 \times 6 = 30$. We are told that inscribed tablets must be displayed in groups of 7, so we seek the greatest multiple of 7 that is less than or equal to 30. The multiples of 7 below 30 are $7, 14, 21, 28$. The greatest is $28$. Therefore, the largest number of inscribed tablets that can be grouped in sevens is $28$. - go-checkin.com