Solution: The divisors of 120 are $ 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120 $. Those divisible by 5 are $ 5, 10, 15, 20, 30, 40, 60, 120 $. Summing them: $ 5 + 10 + 15 + 20 + 30 + 40 + 60 + 120 = 290 $. oxed290Question: Let $ x $ and $ y $ be positive real numbers representing the bandwidths (in Gbps) of two parallel data streams. Find the minimum value of