Solution: The area of the incircle is $ \pi c^2 $. For a right triangle, the semiperimeter $ s = \fraca + b + z2 $, and the inradius $ c = \fraca + b - z2 $. The area of the triangle is $ r \times s = c \times (z + c) $. Therefore, the ratio is $ \frac\pi c^2c(z + c) = \frac\pi cz + c $. The answer is $ \boxed\dfrac\pi cz + c $. - go-checkin.com