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"Shaved-In Strength: Train Adductor Muscles Like a Pro Instantly! - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 A_{ ext{sector}} = rac{1}{2} r^2 heta = rac{1}{2} \cdot 16 \cdot rac{2\pi}{3} = rac{16\pi}{3}

📌 Area of triangle \(OAB\):

📌 A_{ ext{triangle}} = rac{1}{2} ab \sin heta = rac{1}{2} (2\sqrt{6})(2\sqrt{6}) \sin\left(rac{2\pi}{3}

📌 ight) = rac{1}{2} \cdot 24 \cdot rac{\sqrt{3}}{2} = 6\sqrt{3}

📌 Area of segment (the smaller region bounded by the chord and arc) is:

📌 A = A_{ ext{sector}} - A_{ ext{triangle}} = rac{16\pi}{3} - 6\sqrt{3}

📌 But since the line \(y = x + 2\) cuts the circle from top-right to bottom-left, the region enclosed is actually the smaller segment. Hence, the area is:

📌 oxed{rac{16\pi}{3} - 6\sqrt{3}}

🔥 Popular Posts

So again, contradiction.
So the only way to resolve this is to define theQuestion: A chemical e...
Solution: To determine when the concentration is increasing, we analyz...
C'(t) = rac{(3)(t^2 + 4) - (3t + 2)(2t)}{(t^2 + 4)^2}
3(t^2 + 4) - 2t(3t + 2) = 3t^2 + 12 - (6t^2 + 4t) = -3t^2 - 4t + 12
C'(t) = rac{-3t^2 - 4t + 12}{(t^2 + 4)^2}
To find where $ C(t) $ is increasing, we solve:
-3t^2 - 4t + 12 > 0
This is a quadratic inequality. First, find the roots:
-3t^2 - 4t + 12 = 0 \Rightarrow 3t^2 + 4t - 12 = 0

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