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Home » For $ x > 8 $, test $ x = 9 $: $ \frac112 > 0 $. - go-checkin.com

For $ x > 8 $, test $ x = 9 $: $ \frac112 > 0 $. - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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\(D' = 10x + 14\). Set to zero:
\(10x + 14 = 0 \Rightarrow x = -rac{7}{5}\)
Then \(y = 2(-rac{7}{5}) + 3 = -rac{14}{5} + rac{15}{5} = rac{1}{5...
Thus, the closest point is \(\left(-rac{7}{5}, rac{1}{5}
ight)\)
oxed{\left(-rac{7}{5},\ rac{1}{5}
Question: Find the minimum value of \((\cos x + \sec x)^2 + (\sin x +...
Solution: Expand both squares:
\cos^2 x + \sin^2 x + 4 + \sec^2 x + \csc^2 x = 1 + 4 + rac{1}{\cos^2...
So total expression is:

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