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Home » Find the value of $ \fraca^3b^3 + \fracb^3a^3 $. - go-checkin.com

Find the value of $ \fraca^3b^3 + \fracb^3a^3 $. - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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10! = 3628800,\quad 3! = 6,\quad 5! = 120,\quad 2! = 2
\frac{3628800}{6 \cdot 120 \cdot 2} = \frac{3628800}{1440} = 2520
Thus, there are 2520 distinct activation sequences.
\boxed{2520}
Question: An AI startup trains a model using 6 identical blue data bat...
Solution: We compute the number of distinct permutations of a multiset...
\frac{13!}{6! \cdot 4! \cdot 3!}
Compute step-by-step:
13! = 6227020800,\quad 6! = 720,\quad 4! = 24,\quad 3! = 6
\frac{6227020800}{720 \cdot 24 \cdot 6} = \frac{6227020800}{103680} =...

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