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Home » $B = (1, \sqrt3)$ → not integer - go-checkin.com

$B = (1, \sqrt3)$ → not integer - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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z^2 = c \cdot r \left(1 - rac{r^2}{c^2}
ight) = c r - rac{r^3}{c}
But \(r = rac{\sqrt{x^2 + y^2}}{1}\), so:
z^2 = c \sqrt{x^2 + y^2} - rac{(x^2 + y^2)^{3/2}}{c}
This is messy. Instead, return to the standard geometric interpretatio...
We know that the equation \(
ho = c \sin\phi\) in spherical coordinates represents a **sphere**.
Multiply both sides by \(
ho^2 = c
ho \sin\phi

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