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A_\textnew = 64 \times 2.25 = 144 - go-checkin.com

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P'(x) = -\frac{5000}{x^2} + 0 - 0.5 = -\frac{5000}{x^2} - 0.5
Set \( P'(x) = 0 \):
-\frac{5000}{x^2} - 0.5 = 0 \Rightarrow \frac{5000}{x^2} = -0.5
This yields a negative right-hand side, which is impossible. But note:...
P'(x) = -\frac{5000}{x^2} - 0.5
This is always negative, meaning \( P(x) \) is decreasing? But that ca...
Actually,
P(x) = \frac{5000}{x} + 120 - 0.5x
P'(x) = -\frac{5000}{x^2} - 0.5 \quad \text{— still negative?}
Wait — no, derivative of \( -0.5x \) is \( -0.5 \), derivative of \( 5...

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