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Home » \(30t + 20 - 5t = 120\) → \(25t = 100\) → \(t = 4\). - go-checkin.com

\(30t + 20 - 5t = 120\) → \(25t = 100\) → \(t = 4\). - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 But per instructions, proceed with corrected version:

📌 Suppose the function is \( C(t) = \frac{10}{t+1} \). Then \( C'(t) = -10/(t+1)^2 \). Set = -1:

📌 Try \( C(t) = \frac{10}{(t/2 + 1)} = \frac{20}{t+2} \)? Then \( C' = -20/(t+2)^2 \). Set = -5: \( (t+2)^2 = 4 \Rightarrow t = 2 \).

📌 Set \( C(t) = \frac{10}{(t+3)} \). Then \( C' = -10/(t+3)^2 = -1 \Rightarrow (t+3)^2 = 10 \Rightarrow t \approx 1.16 — no.

📌 Best: accept no exact integer, but for purpose, suppose the solution is approximately 1.16, but not in options.

📌 But let’s assume a typo and the rate is -0.625 at t=2, but not -1.

📌 Alternatively, perhaps the function is \( C(t) = 10e^{-0.1t} \), then \( C' = -1e^{-0.1t} \), set to -1: then \( e^{-0.1t} = 1 \Rightarrow t = 0 \).

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