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\[ a_n = a_1 \cdot r^n-1 \] - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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\frac{1}{2} \times b \times \sqrt{100 - \frac{b^2}{4}} = 48
Solving for \(b\) involves trial or algebraic manipulation, but instea...
h' = \sqrt{100 - \frac{(b+4)^2}{4}}
\frac{1}{2} \times (b + 4) \times h'
\frac{1}{2} \times (b + 4) \times h' - 48
Assuming \(b = 8\) (from solving the quadratic equation derived from a...
h = \sqrt{100 - 16} = \sqrt{84} \approx 9.165
The new height \(h'\) becomes:
h' = \sqrt{100 - \frac{(8+4)^2}{4}} = \sqrt{100 - 36} = \sqrt{64} = 8
\frac{1}{2} \times 12 \times 8 = 48

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