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\[ 3k + 2k = 5k = -b \] - go-checkin.com

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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E(t+1) - E(t) = 2t + 1, \quad E(0) = 0.
This is a first-order difference equation. The difference $ E(t+1) - E...
From the initial condition:
E(0) = c = 0.
Now compute the difference:
E(t+1) - E(t) = a(t+1)^2 + b(t+1) - (at^2 + bt) = a(2t+1) + b = 2at +...
Set equal to $ 2t + 1 $:
2at + (a + b) = 2t + 1.
2a = 2 \Rightarrow a = 1, \quad a + b = 1 \Rightarrow 1 + b = 1 \Right...
Thus, $ E(t) = t^2 $.

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